\(\int \frac {x^2}{\log (c (a+b x^2)^p)} \, dx\) [106]

Optimal result

Integrand size = 18, antiderivative size = 18 \[ \int \frac {x^2}{\log \left (c \left (a+b x^2\right )^p\right )} \, dx=\text {Int}\left (\frac {x^2}{\log \left (c \left (a+b x^2\right )^p\right )},x\right ) \]

[Out]

Unintegrable(x^2/ln(c*(b*x^2+a)^p),x)

Rubi [N/A]

Not integrable

Time = 0.01 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {x^2}{\log \left (c \left (a+b x^2\right )^p\right )} \, dx=\int \frac {x^2}{\log \left (c \left (a+b x^2\right )^p\right )} \, dx \]

[In]

Int[x^2/Log[c*(a + b*x^2)^p],x]

[Out]

Defer[Int][x^2/Log[c*(a + b*x^2)^p], x]

Rubi steps \begin{align*} \text {integral}& = \int \frac {x^2}{\log \left (c \left (a+b x^2\right )^p\right )} \, dx \\ \end{align*}

Mathematica [N/A]

Not integrable

Time = 0.21 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.11 \[ \int \frac {x^2}{\log \left (c \left (a+b x^2\right )^p\right )} \, dx=\int \frac {x^2}{\log \left (c \left (a+b x^2\right )^p\right )} \, dx \]

[In]

Integrate[x^2/Log[c*(a + b*x^2)^p],x]

[Out]

Integrate[x^2/Log[c*(a + b*x^2)^p], x]

Maple [N/A]

Not integrable

Time = 0.04 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.00

\[\int \frac {x^{2}}{\ln \left (c \left (b \,x^{2}+a \right )^{p}\right )}d x\]

[In]

int(x^2/ln(c*(b*x^2+a)^p),x)

[Out]

int(x^2/ln(c*(b*x^2+a)^p),x)

Fricas [N/A]

Not integrable

Time = 0.29 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.11 \[ \int \frac {x^2}{\log \left (c \left (a+b x^2\right )^p\right )} \, dx=\int { \frac {x^{2}}{\log \left ({\left (b x^{2} + a\right )}^{p} c\right )} \,d x } \]

[In]

integrate(x^2/log(c*(b*x^2+a)^p),x, algorithm="fricas")

[Out]

integral(x^2/log((b*x^2 + a)^p*c), x)

Sympy [N/A]

Not integrable

Time = 1.57 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.83 \[ \int \frac {x^2}{\log \left (c \left (a+b x^2\right )^p\right )} \, dx=\int \frac {x^{2}}{\log {\left (c \left (a + b x^{2}\right )^{p} \right )}}\, dx \]

[In]

integrate(x**2/ln(c*(b*x**2+a)**p),x)

[Out]

Integral(x**2/log(c*(a + b*x**2)**p), x)

Maxima [N/A]

Not integrable

Time = 0.24 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.11 \[ \int \frac {x^2}{\log \left (c \left (a+b x^2\right )^p\right )} \, dx=\int { \frac {x^{2}}{\log \left ({\left (b x^{2} + a\right )}^{p} c\right )} \,d x } \]

[In]

integrate(x^2/log(c*(b*x^2+a)^p),x, algorithm="maxima")

[Out]

integrate(x^2/log((b*x^2 + a)^p*c), x)

Giac [N/A]

Not integrable

Time = 0.36 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.11 \[ \int \frac {x^2}{\log \left (c \left (a+b x^2\right )^p\right )} \, dx=\int { \frac {x^{2}}{\log \left ({\left (b x^{2} + a\right )}^{p} c\right )} \,d x } \]

[In]

integrate(x^2/log(c*(b*x^2+a)^p),x, algorithm="giac")

[Out]

integrate(x^2/log((b*x^2 + a)^p*c), x)

Mupad [N/A]

Not integrable

Time = 1.40 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.11 \[ \int \frac {x^2}{\log \left (c \left (a+b x^2\right )^p\right )} \, dx=\int \frac {x^2}{\ln \left (c\,{\left (b\,x^2+a\right )}^p\right )} \,d x \]

[In]

int(x^2/log(c*(a + b*x^2)^p),x)

[Out]

int(x^2/log(c*(a + b*x^2)^p), x)